I'm trying to figure out why the number of points ($Np$) equals any Prime ($P$) when:
$P \equiv 2 \pmod 3$
To the Elliptic Curve $y^2=x^3+17$
Does anyone know why this is?
I'm trying to figure out why the number of points ($Np$) equals any Prime ($P$) when:
$P \equiv 2 \pmod 3$
To the Elliptic Curve $y^2=x^3+17$
Does anyone know why this is?
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If $p \neq 1 \pmod 3$ then $x \mapsto x^3$ is a permutation of $\Bbb F_p$, and so for each $y \in \Bbb F_p$ there is a unique $x \in \Bbb F_p$ such that $x^3 = y^2-17$