Encode the word A11B modulo 37 using the encoding 0=0, 1=1, . . . , 9=9, A=10, B=11, . . . , Z=35, blank space=36.
I took the weighted sum: 5(10) + 4(1) + 3(1) + 2(11) + 1(c) ≡ 0 mod 37 Solving, i got c ≡ 32 mod 37, which is V. hence getting A11BV
However the solution given is A11BI, which is the correct answer? And why?
Thanks