Equation involving floor function:

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Given n a natural number, find $x$ (positive real number) such that: $$ 6\lfloor x \rfloor=n, $$ where $ \lfloor x \rfloor $ represents the value of the floor function in x.

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For $n>1$, a solution is $$x=(n+1)^{1/n}.$$ To prove it, use induction to show that $n+1<2^n$ for all $n>1$.