Hey guys so I am trying to do this 3d calc problem and I am stuck. We went over how to find the equation of the plane when given two lines in a different format, but I am not exactly sure how to pull the information out of what is given and get the equation. I am not sure what two vectors I am suppose to get to cross product, any help would be greatly appreciated.
Find an equation of the plane that contains the line and parallel to the given plane.
$$x = 5 + 2t, y = t, z = 6 - t$$
$$2x + 4y + 8z = 18$$
since the searched plane is parallel to the given plane we get $$2x+4y+8z=d$$ plugging the given equation for the line in this plane we have $$2(5+2t)+4t+8(6-t)=d$$ from here we get $d=58$