This is a follow up to my previous question on the equational identities of the $(+,*,0,1)$ reducts of commutative rings. In this question, I want to consider the equational identities of the $(+,*,0,1)$ reducts of rings, not necessarily commutative. I conjecture that
- $x+0=x$
- $x+y=y+x$
- $(x+y)+z=x+(y+z)$
- $x*1=x$
- $1*x=x$
- $(x*y)*z=x*(y*z)$
- $x*(y+z)=(x*y)+(x*z)$
- $(x+y)*z=(x*z)+(y*z)$
- $x*0=0$
- $0*x=0$
is a sufficient finite basis. Is this true?