Let $(X, \|\cdot\|)$ be a normed linear space of dimension $n < \infty$.
Is it always true that we can find a sequence of $m = n + 1$ points $x_i$ such that $\|x_i - x_j\| = c > 0$ for all $i\neq j$?
Can we choose $m$ to be bigger than $n+1$ without violating the first property?
In case $X$ is not finite-dimensional, does there always exist a countable sequence of $x_i$ with the desired property?
Inspired by this question.
It is easy to see that it is not possible in $n=1$ or $n=2$. This implies that it is not possible in higher dimensions. If it were possible in dimension $n$, delete a point and then it would be possible in dimension $n-1$.
The quoted construction can be carried out in an infinite dimensional Hilbert space. For a general Banach space, I do not know.
Edit
After reading Ilya's comment I realized that at least in some Banach space the answer to 2. and 3. is positive. In $\mathbb{R}^n$ with the norm of the maximum there are $2^n$ different points with mutual distance equal to $1$: $(e_1,\dots,e_n)$ where $e_i=0$ or $1$. In $\ell^\infty$ this gives an uncountable set of points with mutual distance $1$. So the question is wether this is true on any Banach space.