(Edited to directly present the problem only, for any future readers. The original question can be read in the revision history.)
Is the following correct?
$$\frac{d}{dy}\left(\int y\,dx\right) = x$$
If not what is the correct solution?
(Edited to directly present the problem only, for any future readers. The original question can be read in the revision history.)
Is the following correct?
$$\frac{d}{dy}\left(\int y\,dx\right) = x$$
If not what is the correct solution?
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Let's use a bit more precise notation and define $f(x)=x^3+x^2$. Then, with $y=f(x)$, we can write
$$\begin{align} z(x)&=\frac{d}{dy}\int f(x)\,dx\\\\ &=\left . \left(\frac{d}{dy}\int y\,\frac{df^{-1}(y)}{dy}\,dy\right)\right|_{y=f(x)}\\\\ &=\left. \left(y\frac{df^{-1}(y)}{dy}\right)\right|_{y=f(x)} \end{align}$$