I should show that function $H(w)=\int_{-\pi}^{\pi}f(x) e^{iwx}dx$, where $f(x)\in L^2(-\pi,\pi)$, is such that $H(re^{i\theta})=O(e^{\pi r |sin(\theta)|})$. Any suggestion?
2025-01-12 19:16:46.1736709406
Estimate of a (integral) function
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Notice that $|e^{ire^{i\theta}x}| = e^{{\rm Re}(ire^{i\theta}x)} = e^{-xr\sin(\theta)}$.
Use Cauchy-Schwarz inequality to estimate $\displaystyle \int_{-\pi}^{\pi}f(x)\cdot 1\, dx$.