Evaluate $\frac{3}{4}$ to the power of $-3$

Question

I have gotten to the next stage where you write it as $\frac{1}{\left(\frac 34\right)}$ to the power of $3$, now I am stuck

I've got it now, thanks everyone.

Answer 1

Hint: $$\left(\frac{b}{a}\right)^{-n} = \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n}$$

Answer 2

$$=\left(\frac{3}{4}\right)^{-3}=\left(\frac{1}{\frac{3}{4}}\right)^3=\left(\frac{4}{3}\right)^3=\frac{4^3}{3^3}=\frac{64}{27}\approx2.37$$

Answer 3

it is $(\frac{4}{3})^3=\frac{4^3}{3^3}=\frac{64}{27}$