Evaluate $\int_c z^2\ dz$, where the curve $c$ is the line $x^2+y^2=\tan^{-1}(x,y)$

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given the line $c$: $\Re(z)^2+\Im(z)^2=\arg(z),$

x^2+y^2=\tan^{-1}(x,y)where $y$ is the imaginary part and $x$ is the real $$$$i want to evaluate $$\int_C z^2\ dz, z=x+iy$$ so: $$ \int_C z^2\ dz=\int_C\left(x+iy\right)^2\left(dx+idy\right){=\int_C\left[\left(x^2-y^2\right)dx-2xy\ dy\right]+i\int_C\left[2xy\ dx+\left(x^2-y^2\right)dy\right]} $$im stack here, how can i continue?

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Hint. Note that $$\int_{\gamma}z^2dz=\left[\frac{z^3}{3}\right]_{P}^Q$$ where $P$ is the starting point and $Q$ is the final point of the path $\gamma$.

P.S. BTW, what is the definition of $\arg(z)$? Is it the principal value with range $[0,2\pi)$?