I have to evaluate: $$\int\frac{1}{(\sqrt{d^2 + x^2})^3}dx$$
$x$ is a variable and $d$ is a constant.
I know that $$\int\frac{1}{(d^2 + x^2)}dx$$ has a trivial solution through trigonometric substitution.
However, I'm having some trouble while trying to apply this knowledge to this particular problem. Maybe it has something to do with integration by parts, but I'm clueless about what would be the next step.
Any clever tricks/shortcuts are also welcome.
The solution should be: $$\frac{x}{d^2(\sqrt{d^2 + x^2})} + c$$.
It can be done by substitution.
Factor out the $d$ from the square root and set $\tan\theta = \frac{x}{d}$.
Use the fact that $(1+\tan^2 \theta)$ is $\frac{1}{\cos^2\theta}$, and $dx = d*\frac{\sin \theta}{\cos^2\theta}d\theta$.
It should become trivial after that.