Evaluate the following indefinite integral. $$ \int {(\tan x)}^{\frac{1}{3}} dx $$ How could i do this integral ?
I tried multiplying the numerator by ${(\sec x)}^2$ and denominator by $1+{(\tan x)}^2$ but getting stuck after putting $\tan x=t$.
Evaluate the following indefinite integral. $$ \int {(\tan x)}^{\frac{1}{3}} dx $$ How could i do this integral ?
I tried multiplying the numerator by ${(\sec x)}^2$ and denominator by $1+{(\tan x)}^2$ but getting stuck after putting $\tan x=t$.
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