Possible Duplicate:
Zero to zero power
From what I understand $0^0$ is indeterminate, yet when you evaluate $\lim\limits_{x\to 0}x^0$ you get 1 (given on wolframalpha.com). Something seems wrong about this.
If wolframalpha is correct, how can this be?
Your limit is correct. The trouble is that is not the only way to approach $0^0$.
Consider $0^x$, $x>0$. Then the limit as $x$ approaches $0$ from above is equal to $0$. For the limit to exist, every pair of functions $f(x), g(x)$, with both functions approaching $0$ as $x \to 0$, must agree on $$\lim_{x \to 0} f(x)^{g(x)}$$
and these two examples show there are distinct pairs of functions which disagree on the limit.
(in this context, we might restrict to $f, g$ being nonnegative functions, but the same principle applies)