$$I=\int_{-1}^{2} {\lfloor{x} \rfloor{}}^{x-\lfloor{x} \rfloor{}}dx=\int_{-1}^{0} {(-1)}^{x+1} +0+1$$ So, I=$-\int_{-1}^{0} {\exp}^{\iota\pi{x}}dx +1=\frac{{2\iota}+{\pi}}{\pi}$ Is my answer is true ? Can someone suggest me another method for doing this integral ?
2026-04-06 13:11:27.1775481087
Evaluating $\int_{-1}^2 {\lfloor x\rfloor}^{x-\lfloor x\rfloor}dx$
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