Evaluate $$\int (\sin x)^2\,dx$$
Anyone can guide me for this?
Thank you!
Write $(\sin x)^{2} = \dfrac{1 - \cos 2x }{2}$. No need of substitution or by parts
Hint: $\quad \sin^2 x = \tfrac{1}{2}( 1 - \cos 2x)$
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Write $(\sin x)^{2} = \dfrac{1 - \cos 2x }{2}$. No need of substitution or by parts