Evaluating integral by parts.

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Evaluate the following integral.

$$ \int e^{2x}\sin{5x}\ dx $$

What I have tried :

$ g(x) = \sin5x , f^{'}(x) = e^{2x} , f(x) = e^{2x} $

$$ \int e^{2x}\sin{5x}\ dx = e^{2x}\sin{5x} -\int e^{2x}\ 5\cos{}5x\ dx $$ $$e^{2x}\sin{5x}-5[e^{2x}\cos{5x}- \int e^{2x}-5\ \sin{5x}\ dx]$$ $$e^{2x}\sin{5x}-5[e^{2x}\cos{5x}- 5\int e^{2x}\sin{5x}\ dx]$$

$$\int e^{2x}\sin{5x}\ dx = e^{2x}\sin5x - 5e^{2x}\cos5x + 25\int e^{2x}\sin5x\ dx$$

$$-24\int e^{2x}\sin5x\ dx = e^{2x}\sin5x-5e^{2x}\cos5x$$

$$ \int e^{2x}\sin5x\ dx = \frac{e^{2x}\sin5x-5e^{2x}\cos5x}{-24} $$

The answer in the book is $ \frac{2}{29}e^{2x}\sin5x-\frac{5}{29}e^{2x}\cos5x+C $

Where is my mistake ?

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The integral of $e^{2x}$ is, $\int e^{2x}dx = \frac{e^{2x}}{2} + c$. That's your (first) mistake. I didn't look for more.