Prove that every torsion free divisible abelian group $D$ is direct sum of the copies of the $\mathbb{Q}$.
If $a\in D$ then there exists unique $b \in D$ and $n\neq 0 \in \mathbb{Z} $ such that a=nb. Now, D is torsional free means that every element except identity is not of finite order. b can be written as b= 1/n a but I am unable to think which result should I use now?
Can you outline a complete proof?
Here are some hints, if you can answer these, you should have your proof.