Can you give me an example of a bounded function $f\in L^1[a,b]$ which $f\not\in L^2[a,b]$?
Thank you
It is not possible since $$\int_{[a,b]}{|f(x)|^{2} \, d\lambda(x) } \leq M_{f}\int_{[a,b]}{|f(x)| \, d\lambda(x)} < \infty$$
Where $M_{f}>0$ is a bound of $f$
Moreover $$L^{\infty}[a,b] \subset L^{2}[a,b]$$
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It is not possible since $$\int_{[a,b]}{|f(x)|^{2} \, d\lambda(x) } \leq M_{f}\int_{[a,b]}{|f(x)| \, d\lambda(x)} < \infty$$
Where $M_{f}>0$ is a bound of $f$
Moreover $$L^{\infty}[a,b] \subset L^{2}[a,b]$$