Our linear algebra prof gave us this problem and I am not quite sure how to go about starting or what it is asking for.
Give an example of a nonempty subset $U$ in $R^2$ such that $U$ is closed under scalar multiplication, but $U$ is not a linear subspace of $R^2$.
This is what closed means in this context:
A subset $U \subseteq \mathbb{R}^2$ is said to be closed under scalar multiplication if the following holds:
$$\text{For every } \mathbf{x} \in U \text{ and } c \in \mathbb{R},\ c\mathbf{x} \in U$$
So he wants you to find a subset $U$ satisfying the above property but is NOT a subspace.
In this context, a subset $V\subseteq \mathbb{R}^2 $ is a subspace if:
$\mathbf{0} \in V$
V is closed under scalar multiplication
If $\mathbf{x,y}\in V$, then $\mathbf{x}+\mathbf{y} \in V$
So you need to find a subset $U$ that satisfies #2 but fails to satisfy #1 or #3. Hint: Really it will be #3 as #2 implies #1 if $U$ is non-empty.