I am trying to find an example of ode, $x^{‘}=f(t,x)$, where $f$ does not satisfies Picard-Lindelöf theorem, but it still have unique solution.
Is it possible?
I am trying to find an example of ode, $x^{‘}=f(t,x)$, where $f$ does not satisfies Picard-Lindelöf theorem, but it still have unique solution.
Is it possible?
Yes, it is.