How would I go about computing $$(1 2 3)\cdot(12)(34)$$
I know the definitions but I do not know how to apply them here. This is rather strange and odd-looking to me. I know I have to construct a natural group (1234), relate it to the product, but then what?
On
If $(1 2)(3 4) \in S_n$, $(12)(34)$ is notation for the function $f : \{1, \dots, n\} \to \{1, \dots, n\}$, $f(1) = 2$, $f(2) = 1$, $f(3) = 4$, $f(4) = 3$, $f(i) = i$ for $5 \leq i \leq n$. Likewise, $(1 2 3)$ is notation for the function $g : \{1, \dots, n\} \to \{1, \dots, n\}$, $g(1) = 2$, $g(2) = 3$, $g(3) = 1$, $g(j) = j$ for $4 \leq j \leq n$. Then $(1 2 3)\cdot(1 2)(3 4)$ is the function $g\circ f : \{1, \dots, n\} \to \{1, \dots, n\}$.
On
The operators represent the translations relative to an initial starting position $1234$. If you want to apply it successively, you have to suppose that the numbers in the operators are not the numbers in what's currently displayed. You could use letters to represent the starting point, like $abcd$.
In any case, $(1,2)(3,4) \cdot 1,2,3,4$ gives $2,1,4,3$. Applying $(1,2,3) \cdot 2,1,4,3$ rotates the first three elements, to give $1,4,2,3$.
You can directly derive $1,4,2,3$ from $1,2,3,4$ by rotating the triplet $2,3,4$, ie $(2,3,4)$
So the operation $(1,2,3) \cdot (1,2)(3,4) = (2,3,4)$
$1$ is sent to $2$, which is in turn sent to $3$. Thus $1$ goes to $3$.
$2$ is sent to $1$, which is sent to $2$. Thus $2$ goes to $2$.
$3$ is sent to $4$, which is no longer messed with. Thus $3$ goes to $4$.
What does $4$ go to? What is the resulting permutation?