Question
Say whether it is true or false that exist $f\colon\mathbb R\longrightarrow\mathbb R$ is a monotonic, non-constant and periodic function of period $T>0$ ?
Question
Say whether it is true or false that exist $f\colon\mathbb R\longrightarrow\mathbb R$ is a monotonic, non-constant and periodic function of period $T>0$ ?
On
a monotonic, non-constant, periodic function of period $T>0$, then $f$ is continuous.
It's a vacuous statement:
If $f$ is non-constant, then there are numbers $x$ and $y$ such that $$y>x \quad\text{ and } \quad f(y)\neq f(x)$$
Now $f$ is periodic, i.e. there exists $x'>y$ such that $f(x')=f(x)$ and hence:
If $f(y) > f(x) = f(x')$ then $f$ is not monotonic.
If $f(y) < f(x) = f(x')$ then $f$ is not monotonic, either.
Thus no such function exists, thus every such function is constant :-)
Suppose $f:\mathbb R\to\mathbb R$ is increasing and has period $T$. Take any $x\in\mathbb R$, then $f(x) = f(x+T)$ implies $f$ is constant on $[x,x+T]$ due to monotonicity. So $f$ must be constant. Hence,
is vacuously true.