Given that $f =f(y)$ differential on $\mathbb{R}$, given the initial value $y(x_0) =y_0$ prove that there is a solution to $y' = f(y)$ and its unique ?
I try to solve it with no luck, i am stuck in the very beginning.
Given that $f =f(y)$ differential on $\mathbb{R}$, given the initial value $y(x_0) =y_0$ prove that there is a solution to $y' = f(y)$ and its unique ?
I try to solve it with no luck, i am stuck in the very beginning.
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