Existence of orthonormal basis for subspaces.

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Here's a fact (in bold) I encountered in a proof that I'm having trouble justifying:

Given an orthogonal projector $P$, let it project onto $S_1$ along $S_2$. By definition those sets are orthogonal. Let $\{q_1, \dots , q_m\}$ be an orthonormal basis for $\mathbb{C}^m$, where $\{q_1, \dots, q_n\}$ is a basis for $S_1$ and $\{q_{n+1}, \dots , q_m\}$ is a basis for $S_1$...

How do I know that given an orthogonal projector that I can divide an orthonormal basis for the whole vector space into parts that form an orthonormal basis for the complementary subspaces formed by an orthogonal projector?

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The bolded sentence doesn't mean you can divide any such basis this way. It means you can choose a particular basis using this strategy.

The strategy is to choose an arbitrary basis for $S_1$ and an arbitrary basis for $S_2$. Then combine them. Since $S_1$ and $S_2$ are orthogonal complements, the combined basis spans the whole space; since every vector in $S_1$ is orthogonal to every vector in $S_2$, and each individual basis is orthonormal, the combined basis is orthonormal.