Existence of transversals of subgroups implies axiom of choice?

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If $G$ is a group and $H\leq G$ is a subgroup, then a transversal of $H$ is a subset $T\subseteq G$ which meets every coset of $H$ in a unique point.

The axiom of choice clearly implies that every subgroup of a group has a transversal. But does the converse hold? I'm sure somebody must have proved this, but I haven't been able to find a reference.

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Keremedis, K. "Some equivalents of AC in algebra. II". Algebra Universalis 39 (1998), no. 3-4, 163–169.

The first theorem proves that requiring this just for Abelian groups is enough to prove the axiom of choice.