$$4^x + 4^y = 10$$ $$4^x - 4^y = 8$$ $$2^x . 2^y = ?$$ I couldn't understand this problem, also i couldn't solve the problems which like this. So I want to learn how to solve this problems are. Thanks for helping!
2026-04-18 12:57:10.1776517030
Exponential Equation Prob
43 Views Asked by Bumbble Comm https://math.techqa.club/user/bumbble-comm/detail At
2
Try adding and subtracting the equations.
Adding we get $2\times4^x=18\implies4^x=3^2\implies2^{2x}=3^2\implies (2^x)^2=3^2$.Taking square root $2^x=3$
Subtracting we get,$2\times4^y=2\implies 4^y=4^0\implies y=0$.So,$2^y=2^0=1$
So,now, just plug in the values of $x$ and $y$ into $2^x\cdot2^y=3\cdot1=3 $