I am trying to solve the following exponential equation where the variable is squared. Most likely it is not difficult, but I am just missing the technique: what is the way to solve an exponential equation when the variable is a square? Thanks.
$$ 2^x{^{^2}}+2^1{^{-x{^2}}} = 3 $$
Hint:
Your equation is: $$ 2^{x^2}+\frac{2}{2^{x^2}}=3 $$ for: $y=2^{x^2}$ becomes $$y+\frac{2}{y}=3$$ that you can solve for $y$.