Express $27\cdot16^{11}+16^7+33\cdot16^4-16^4$ as a hexadecimal number

Question

Question: Express $$\large27\cdot16^{11}+16^7+33\cdot16^4-16^4$$ as a hexadecimal number.

Answer 1

$$27(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=16(16^{11})+11(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+33(16^4)-(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+32(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+2(16)(16^4)$$ $$=(16^{12})+11(16^{11})+(16^7)+2(16^5)$$ $$=1B00010200000_{16}$$