Here is my draft of Answer.
Suppose p is a prime number, P€N and p not equal to1, and for all a€N, for all b € N, if P=a•b then a =1 or b=1
My questions: 1. Do I express the definition of prime in the language of quantifiers correctly? And how to show “ and “ “ if” in quantifiers type?
- How do we negate this? Just add a negation mark? And change “ for all” to “there exists”?
Thanks
Don't start with: "suppose $p$ is a prime number ..." You are not giving a proof, but rather stating a definition.
So, start with "$p$ is a prime number if and only if ..."
And yes, you got all the conditions correct: "$p$ is a prime number iff $p \in \mathbb{N}$ and $p \not = 1$ and for all $a \in \mathbb{N}$ and $b \in \mathbb{N}$: if $p = a \cdot b$ then $a=1$ or $b=1$"
In first-order logic, this can be translated as:
$$\forall p ( Prime(p) \leftrightarrow (p \in \mathbb{N} \land p \not = 1\land \forall a \forall b ((a \in \mathbb{N} \land b \in \mathbb{N} \land p = a \cdot b) \rightarrow (a=1 \lor b=1))))$$