Express the magnitude squared of the cross product of vectors a & b in terms of |a|, |b| and cos(Theta)

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$|a\times b| = |a||b|\sin\theta$, so $|a\times b|^2 = |a|^2 |b|^2 \sin^2\theta = |a|^2 |b|^2 (1-\cos^2\theta)$.

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$|a|^2|b|^2(1-\cos^2\theta)$, since $|a×b|=|a||b|\sin\theta$.