The question arises from the rewording of some theorems, by example continuity of a function $f$, we have that
$$f\text{ is continuous at }c\iff (\forall\epsilon>0,\exists\delta>0:|x-c|<\delta\implies|f(x)-f(c)|<\epsilon)\tag{1}$$
then I think I can reword this as
$$f\text{ is continuous at }c\iff ((|x-c|<\delta\implies|f(x)-f(c)|<\epsilon)\implies (\forall\epsilon>0,\exists\delta>0))$$
The last statement seem strange to read but the last implication seems logically equivalent to $(1)$. Anyway this is just an experiment.
My question is, there is some expression logically equivalent to "such that" that can be written with basic logical operators as $\lor$, $\land$, $\lnot$, $\iff$ and $\implies$? Thank you in advance.
No, you can't do that; that's not how quantifiers (or conditionals) work.
"$\forall \epsilon>0$" just means, "For all $\epsilon>0$." It doesn't assert anything - e.g. it doesn't make sense to say ""$\forall \epsilon>0$" is false". Similarly with "$\exists \delta>0$."
So an expression of the form "...$\implies (\forall \epsilon>0,\exists \delta>0)$" is meaningless: "$\implies$" connects two sentences.
The issues go further than this: quantifiers bind variables. The expression "$\forall x(x>5)$" is a sentence; the expression "$x>5$" is not, and the expression "$(x>5)\implies (\forall x)$" is really not.