Extended Topological Quantum Field Theory (ETQFT) by Jacob Lurie

406 Views Asked by At

What is the functorial (categorical) definition of TQFT (Topological Quantum Field Theory), which Jacob Lurie "had extended", for his ETQFT ?

Actually I just need to know what are basic tools, to state properly a categorical definition of a classical TQFT. Thank you very much for your help !

1

There are 1 best solutions below

0
On

This is just one definition of a TQFT. There are many more, but this is the one I personally have encountered before: Let $\mathbf{Bord}(n+1)$ be the category with objects closed, oriented, smooth $n$-manifolds and for $Y_1, Y_2$ two objects in this category, $Hom(Y_1,Y_2)$ be the set of $(n+1)$ bordism classes between $Y_1$ and $Y_2$. An $(n+1)$-TQFT is a symmetric monoidal functor from $\mathbf{Bord}(n+1)$ to the category $\mathbf{Vec}_{\mathbb{C}}$ of finite dimensional complex vector spaces.

More specifically: an $(n+1)$-TQFT is a pair $F=(V,Z)$ where $V(Y)$ assigns a finite dimensional complex vector space to a closed, oriented, smooth $n$-manifold $Y$ and $Z$ assigns to each $(n+1)$-bordism $X$ between two $Y_-,Y_+\in\mathbf{Bord}(n+1)$ a linear map $Z(X):V(Y_-)\to V(Y_+)$ such that:

  1. If $X$ and $X'$ belong to the same bordism class, then $Z(X)=Z(X')$.
  2. $Z(Y\times I)=id_{V(Y)}$
  3. $Z(X_1\cup X_2)=Z(X_2)\circ Z(X_1):V(Y_1)\to V(Y_2)\to V(Y_3)$
  4. $V(\emptyset)\cong\mathbb{C}$
  5. $V(Y_1\sqcup Y_2)\cong V(Y_1)\otimes V(Y_2)$ with the following diagrams commuting: $$\require{AMScd} \begin{CD} V((Y_1\sqcup Y_2)\sqcup Y_3) @>{\cong}>> (V(Y_1)\otimes V(Y_2))\otimes V(Y_3);\\ @VVV @VVV \\ V(Y_1\sqcup( Y_2\sqcup Y_3)) @>{\cong}>> V(Y_1)\otimes(V(Y_2)\otimes V(Y_3)); \end{CD}$$

    $$\require{AMScd} \begin{CD} V(\emptyset\sqcup Y) @>{\cong}>> \mathbb{C}\otimes V(Y);\\ @VVV @VVV \\ V(Y) @>{=}>> V(Y); \end{CD}$$

  6. There is an isomorphism $V(Y_1\sqcup Y_2)\cong V(Y_2\sqcup Y_1)$ such that the following diagram commutes: $$\require{AMScd} \begin{CD} V(Y_1\sqcup Y_2) @>{\cong}>> V(Y_1)\otimes V(Y_2);\\ @VVV @VVV \\ V(Y_2\sqcup Y_1) @>{\cong}>> V(Y_2)\otimes V(Y_1); \end{CD}$$

Subject to these axioms, the functor $F=(V,Z)$ can be anything we like; what we take it to be determines the TQFT we are looking at. There is a theorem which says that: $Z(M)$ is a smooth invariant for closed $(n+1)$-manifolds $M$ and $V(Y)$ is a representation of the mapping class group of $Y$. As far as I am aware, given a TQFT $F=(V,Z)$, it is still an open (and very difficult) question to determine exactly how $F$ relates to 'classical' invariants such as, for example, homology groups or homotopy groups.