$lnQ=1.37+0.632lnK+0.452lnL$
(0.257). (0.219)
$cov(bk,bl)=0.055, R^2=0.98$ $H_0: bk+bl=1$
How can I proceed f-test even though I can't find df and RSS?
$lnQ=1.37+0.632lnK+0.452lnL$
(0.257). (0.219)
$cov(bk,bl)=0.055, R^2=0.98$ $H_0: bk+bl=1$
How can I proceed f-test even though I can't find df and RSS?
Copyright © 2021 JogjaFile Inc.
I would apply the t-test.
$H_0: \beta_k+\beta_l=1$
$H_1: \beta_k+\beta_l\neq 1$
$T=\Large{\frac{\hat \beta_k+\hat \beta_l-1}{\sqrt{var{(\hat \beta_k)} +var{(\hat \beta_l)} -cov(\hat \beta_k,\hat \beta_l)}}}$
You compare the value of T with the value of $t_{(n-3,1-\frac{\alpha}{2})}$. n is the number of observations and $\alpha$ is the significance level.
If $|T|<t$, then you do not reject the Null-Hypothesis.