On my book, determinant is calculated this way: $det(A)= \sum_{j=1}^n (-1)^{i+j} A_{Ij} det(\hat A_{ij})$
Since we can do either column or row, can I switch $det(A)= \sum_{i=1}^n (-1)^{i+j} A_{Ij} det(\hat A_{ij})$? Fact checking.
On my book, determinant is calculated this way: $det(A)= \sum_{j=1}^n (-1)^{i+j} A_{Ij} det(\hat A_{ij})$
Since we can do either column or row, can I switch $det(A)= \sum_{i=1}^n (-1)^{i+j} A_{Ij} det(\hat A_{ij})$? Fact checking.
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