Fake proof of weak convergence $\implies$ strong convergence

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Fake pf: Let $X$ a Banach space, then let $x_n$ converge weakly to $x$, then as $X^* $ norms $X$ it follows that there exits some $ f \in X^*$ such that

$$ ||x_n - x|| = f(x_n-x) = f(x_n) - f(x) $$

by weak convergence $f(x_n) \to f(x) \implies f(x_n) - f(x) \to 0 $


I know this is wrong since the standard schauder basis in $\ell^p$ converges weakly but not strongly, I just do not know where the proof above went wrong.

Thank you!