Find a 4-digit number divisible by 9 and 25.
Answer is 9000.
I can find the greatest number which is divisible by 9 and 25 but 9900 != 9000. What am I doing wrong?
9, 25 | 3
3, 25 | 3
1, 25 | 5
1, 5 | 5
1, 1
LCM(9, 25) = 3 * 3 * 5 * 5 = 225
Dividing 9999 by 225, the remainder is 99.
Required number = (9999 - 99) = 9000
The greatest number of four digit which is exactly divisible by 9, 25 is 9900.