I understand the answer that we can choose the 3 cycle in nC3 ways, but why is there 2 ways to do this? Hence times 2?
Thanks!
I understand the answer that we can choose the 3 cycle in nC3 ways, but why is there 2 ways to do this? Hence times 2?
Thanks!
If i j and k are the chosen elements moved by the cycle, then (ijk) and (ikj) are both 3 cycles on these letters which are different, and there are no others.