Find all integer solutions to the equation $x^2 − x = y^5 − y$.

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My professor gave us a worksheet with diophantine equations including this one he claims that it is one of the easier ones but that it has a unique solution.

Find all integer solutions to the equation $$x^2 − x = y^5 − y$$.

Also my professor will give extra credit for all prime number solutions (x and y).

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Rearranging the equation gives $$(x^2-y^2)-(x-y)=0$$ Now note that $x^2-y^2=(x-y)(x+y)$.

I'll let you take it from here.