Find all positive integers such that $2^n$ divides $3^n-1$.
I tried factoring $3^n-1$ as such: $$3^n-1=(3-1)(3^{n-1}+3^{n-2}+3^{n-3}+\cdots+3+1).$$ But now I'm stuck.
Find all positive integers such that $2^n$ divides $3^n-1$.
I tried factoring $3^n-1$ as such: $$3^n-1=(3-1)(3^{n-1}+3^{n-2}+3^{n-3}+\cdots+3+1).$$ But now I'm stuck.
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