I want to find the integer solutions of
$$3x+y \equiv 2 \pmod{9}$$
We know that $y \equiv2\pmod{3}$, but I don't know how this helps to find the solution which is $ \mathbb{L} = (0, 2) + (1,−3) \cdot \mathbb{Z}$.
I would appreciate any hints.
I want to find the integer solutions of
$$3x+y \equiv 2 \pmod{9}$$
We know that $y \equiv2\pmod{3}$, but I don't know how this helps to find the solution which is $ \mathbb{L} = (0, 2) + (1,−3) \cdot \mathbb{Z}$.
I would appreciate any hints.
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$$y\equiv2-3x\pmod9$$
As $x\equiv0,1,2\pmod3,3x\equiv0,3,6\pmod9$
$$\implies y\equiv2,2-3,2-6\pmod9$$