I was tasked with finding the antiderivative of $8\sin^3(2x)\cos(2x)$
This is what I have $$4\sin^4(2x)-\int24\sin^3(2x)\cos(2x)\,dx$$
I don't know the step after that.
I was tasked with finding the antiderivative of $8\sin^3(2x)\cos(2x)$
This is what I have $$4\sin^4(2x)-\int24\sin^3(2x)\cos(2x)\,dx$$
I don't know the step after that.
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Just observe
$$\int 8\sin^3(2x)\cos (2x)\,dx=4\int\sin^3(2x)\cos (2x)\cdot2\,dx=4\int u^3\,du=...$$