How can I find at least one first order differential equation when the solution for it is $y = x^4$?
Thanks for your help :)
Most basic equation would be simply $ \frac {dy}{dx}$ = 4$x^3$ with initial condition that y(0)=0
You can get infinite solutions by introducing some constant terms or some specific f(x), and restricting them with specific initial conditions.
For eg. take $$ \frac {dy}{dx} = 4x^3+k$$ (where k is some constant)
So, $$dy=(4x^3+k)dx$$ integrating both sides, $$y=x^4+kx+c$$ Now, use y(0)=0
How about taking $$ \frac{dy}{dx} = (4x^3 + px^q + r)?$$ $$y=x^4+ \frac {px^{q+1}}{q+1}+rx+c$$ Again, y(0)=0
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Most basic equation would be simply $ \frac {dy}{dx}$ = 4$x^3$
with initial condition that y(0)=0
You can get infinite solutions by introducing some constant terms or some specific f(x), and restricting them with specific initial conditions.
For eg. take $$ \frac {dy}{dx} = 4x^3+k$$ (where k is some constant)
So, $$dy=(4x^3+k)dx$$
integrating both sides,
$$y=x^4+kx+c$$
Now, use y(0)=0
How about taking $$ \frac{dy}{dx} = (4x^3 + px^q + r)?$$
$$y=x^4+ \frac {px^{q+1}}{q+1}+rx+c$$
Again, y(0)=0