Find both the velocity v and directed distance s after 1.7 seconds.

Question

An object is moving along a coordinate line subject to the indicated acceleration a​ (in centimeters per second per​ second) with the initial velocity $v_0$ ​(in centimeters per​ second) and directed distance $s_0$ ​(in centimeters). Find both the velocity $v$ and directed distance $s$ after 1.7 seconds.

$$\sqrt[3]{2t+1}$$ $v_0=0$, $s_0=10$

Answer 1

Simply do this, acceleration=$\frac{dv}{dt}$

by integration, $$v-v_{0}=\frac{3}{8}(2t+1)^{\frac{4}{3}} - \frac{3}{8}$$ simply put t to get your answer, and further integrate $v$ to get your $s$.

EDIT: Missed that constant of integration.