So i was given this question.
Find det A if A is 3 × 3 and det(2A) = 6.
Trying to solve this i tried to use the fact that
If A is an n × n matrix, then $det(uA)$ = $u^ndetA$ for any number u.
So for this case if i was given the det(uA) would i just divide the 2, so the answer is 3?
Hint : If $A$ is a $3\times 3$-matrix, then $det(2A)=8\ det(A)$