Find det A if A is 3 × 3 and det(2A) = 6.

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So i was given this question.

Find det A if A is 3 × 3 and det(2A) = 6.

Trying to solve this i tried to use the fact that

If A is an n × n matrix, then $det(uA)$ = $u^ndetA$ for any number u.

So for this case if i was given the det(uA) would i just divide the 2, so the answer is 3?

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Hint : If $A$ is a $3\times 3$-matrix, then $det(2A)=8\ det(A)$