Find $$ \int \left(\frac{f(x)}{x^2}\right)^{\frac{1}{2}} dx $$ with $f(x)= \frac{x+2}{2x+3}$
I could'nt go ahead after putting $f(x)$ in the integral..I tried substituting $x$ to $t^2$.It didnt work out.
Any hint for what is should do here?
2026-05-04 12:25:51.1777897551
Find $ \int \left(\frac{f(x)}{x^2}\right)^{\frac{1}{2}} dx $ with $f(x)= \frac{x+2}{2x+3}$
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Hint : Substitute $u=\sqrt{\frac{2x+4}{2x+3}}$