A container made of metal is in the shape of a frustum of a cone mounted on a hollow cylindrical base of the same metallic sheet. The diameter of the two circular ends of the container are 50 cm and 36 cm, the total vertical height of the container is 30 cm and that of the cylindrical base is 6 cm. Also, find the volume of milk the container can hold
What I tried:
Diagram: 
Height of frustum=$30-6=24$ cm
Radius of upper circle=$\dfrac{Diameter}{2}=\dfrac{50}{2}=25$ cm
Similarly radius of lower circular base=$18$ cm
Slant height $l=\sqrt{h^2+(r_1-r_2)^2}$ so $l=25$
Volume of milk $=$ Volume of frustum
My question: Will we include the lower cylinder volume in the total volume of milk container can hold?