Find number of people given a set of ratios

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I've been asked this question:

A luna park with 3 attractions had its people buying tickets for the attractions in the following ratio: 6:5:12 in 2001. There have been 200 more people in 2002 and the ratio was 7:2:5. The number of people in 2002 that visited the third attraction is 2000. How many people visited the first attraction in 2001?

I tried to solve this as follows but the "ratio" notation confuses me so I'm not sure I did it right: $x$ is the number of people visiting the first attraction in 2001

$ (x + \frac{x}{6}5 + \frac{x}{6}12) + 200 = 2000 + \frac{2000}{5}2 + \frac{2000}{5}7$

Is this the right approach or am I getting this wrong? I don't have a clearer text so I can't be more specific than this unfortunately

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Hint:

If the total number of people is $x$, and they visited the attractions in the ratio $6:5:12$, then the first attraction was visited by $\frac{6}{6+5+12}\cdot x$ people, the second one was visited by $\frac{5}{6+5+12}\cdot x$ and the third was visited by $\frac{12}{6+5+12}\cdot x$ people.

Now, you can set the same equations up for the second year, only replace $x$ (which is the number of people in year $2001$) with $y$ (the number of people in the year $2002$).

Of course, the equation connecting $x$ and $y$ should be clear.