There is a continuous time signal
$$y(t)=\sum_{n=-\infty}^{+\infty}{e^{-|6t+n|}}$$
I want to calculate it's period ($T$) however I didn't find any easy way to calculate it. Is there any formula to convert this signal to a periodic signal form? Is it possible to help me?
Based on the help from @metamorphy, the answer can be calculated.
If we assume that:
$$a_n=e^{-|6t+n|}$$ Then we can say that: $$\sum_{n=-\infty}^{+\infty}{a_n} = \sum_{n=-\infty}^{+\infty}{a_{n+6T}}$$ This is true for each $6T \in Z$. if we replace it in our $y(t)$ then we get:
$$y(t)=\sum_{n=-\infty}^{+\infty}{e^{-|6t+n|}}=\sum_{n=-\infty}^{+\infty}{a_n}=\sum_{n=-\infty}^{+\infty}{a_{n+6T}}=\sum_{n=-\infty}^{+\infty}{e^{-|6t+n+6T|}}=\sum_{n=-\infty}^{+\infty}{e^{-|6(t+T)+n|}}=y(t+T)$$
so period of $y(t)$ is $6T \in Z$ and smallest (main) period is $T_0=\frac{1}{6}$