Find root with chord method

Question

With chord method find real root of the equation

$x^3 - 2x+1-{e^x\over2} = 0$ accurate to $0.001$

I can not perform first condition in the method of chords

Answer 1

The chord (or secant, as I understand it) method:

To approximate a root of $f(x) = 0$, from two points $(x_1, f(x_1)$, $(x_2, f(x_2)$, make the line through these two points $L: \frac{y-f(x_1)}{x-x_1} =\frac{y-f(x_2)}{x-x_2} $.

Then, solve for the $x$ that makes $y = 0$.

This is the next $x$; call it $x_3$.

Continue with $x_2$ and $x_3$ and so on until $y$ is sufficiently small.

Is there anything that you do not understand?