Find sum of roots of following equation: $$\frac{1}{x^2} +\frac{1}{(1-x)^2} = \frac{160}{9}.$$
I know we can find sum of roots of $ax^2 +bx+c=0$ and sum of roots is $\frac{-b}{a}$ but I need a fast way for above equation.
Find sum of roots of following equation: $$\frac{1}{x^2} +\frac{1}{(1-x)^2} = \frac{160}{9}.$$
I know we can find sum of roots of $ax^2 +bx+c=0$ and sum of roots is $\frac{-b}{a}$ but I need a fast way for above equation.
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